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  Q 1.1) What is the force between two small charged spheres having charges of 2 × 10 –7 C and 3 × 10 –7  C placed 30 cm apart in the air? Soln:  Given, The Charge on the 1 st  sphere and 2 nd  sphere is q 1  = 2 x 10 -7  C and q 2  = 3 x 10 -7  C The distance between two charges is given by r = 30cm = 0.3m The electrostatic force between the spheres is given by the relation : F =  \frac{1}{4\pi \epsilon _{o}}.\frac{q_{1}q_{2}}{r^{2}} 4 π ϵ o ​ 1 ​ . r 2 q 1 ​ q 2 ​ ​ Here, \epsilon _{o} ϵ o ​  = permittivity of free space and,  \frac{1}{4\pi \epsilon _{o}} 4 π ϵ o ​ 1 ​  = 9 x 10 9  Nm 2 C -2 Force, F =  \frac{9 \times 10^{9} \times 2 \times 10^{-7} \times 3 \times 10^{-7}}{(0.3)^{2}} ( 0 . 3 ) 2 9 × 1 0 9 × 2 × 1 0 − 7 × 3 × 1 0 − 7 ​  = 6 x 10 ‑3  N. The force between the charges will be repulsive as they have the same nature.   Q 1.2) The electrostatic force on a small sphere of charge 0.4...